Obliczenie: LDt8r9 - 1

s =

v^²

/ ( 2* μ* g)

s =

v^²

/ ( 2* μ* g)

$s$ = $\frac{v^{2}}{2\cdot \mu\cdot g}$

s =

v^²

/ 2/ g/ μ

$s$ = $\frac{v^{2}}{2\cdot g\cdot \mu}$

s =

0.5* v^²

/ g/ μ

$s$ = $\frac{0.5\cdot v^{2}}{g\cdot \mu}$