Obliczenie: UZKs0t - 1
sin(α)+sin(γ) =
n
n
|
sin(α)+sin(γ) = n$$sin(\alpha)+sin(\gamma)$$ = $$n$$
sin(α) = n-sin(γ)$$sin(\alpha)$$ = $$n-sin(\gamma)$$
α = arcsin((n-sin(γ)))$$\alpha$$ = $$arcsin((n-sin(\gamma)))$$
α = arcsin(n-sin(γ))$$\alpha$$ = $$arcsin(n-sin(\gamma))$$